Commit 1392ca75 authored by Denis Filatov's avatar Denis Filatov
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Update math syntax

parent 96e01e10
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+3 −3
Original line number Original line Diff line number Diff line
@@ -183,7 +183,7 @@ SetMbObsCamLongAcc C-ASR-SINGLE-OBS ::= {
 * backward (1) and the speedValue is greater than 3,000. (Usually, backward 
 * backward (1) and the speedValue is greater than 3,000. (Usually, backward 
 * drives are far less than 50m long, and with maximum possible acceleration of 
 * drives are far less than 50m long, and with maximum possible acceleration of 
 * 9 m/s^2 (see trigger conditions for LongAcc-ValueTooLarge), max attainable 
 * 9 m/s^2 (see trigger conditions for LongAcc-ValueTooLarge), max attainable 
 * speed is $\sqrt{2*9*50}$ m/s, i.e., 3,000 cm/s.)
 * speed is $`\sqrt{2*9*50}`$ m/s, i.e., 3,000 cm/s.)
 *
 *
 *   - `Speed-ChangeTooLarge`: The acceleration calculated from the change 
 *   - `Speed-ChangeTooLarge`: The acceleration calculated from the change 
 * in speedValue of two consecutive CAMs meets the trigger conditions of 
 * in speedValue of two consecutive CAMs meets the trigger conditions of 
@@ -191,7 +191,7 @@ SetMbObsCamLongAcc C-ASR-SINGLE-OBS ::= {
 *
 *
 * - _SetMbObsEtsiOnlyLongAcc_:
 * - _SetMbObsEtsiOnlyLongAcc_:
 *   - `LongAcc-ValueTooLarge`: The longitudinalAcceleration is greater 
 *   - `LongAcc-ValueTooLarge`: The longitudinalAcceleration is greater 
 * than 90 dm/s^2. (Typical $\mu$ (coefficient of friction between asphalt and 
 * than 90 dm/s^2. (Typical $`\mu`$ (coefficient of friction between asphalt and 
 * rubber) is 0.9, so maximum possible acceleration is 0.9*9.8 m/s^2, i.e., 
 * rubber) is 0.9, so maximum possible acceleration is 0.9*9.8 m/s^2, i.e., 
 * 88.2 dm/s^2.)
 * 88.2 dm/s^2.)
 */
 */