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The formula used for this is now kVarianceBlocks = ((255 + 1 + md_size + md_block_size - 1) / md_block_size) + 1 Notice that md_block_size=64 for SHA256, which results on the magic constant kVarianceBlocks = 6. However, md_block_size=128 for SHA384 leading to kVarianceBlocks = 4. CLA:trivial Reviewed-by:Matt Caswell <matt@openssl.org> Reviewed-by:
Paul Dale <paul.dale@oracle.com> (Merged from https://github.com/openssl/openssl/pull/7342) (cherry picked from commit cb8164b05e3bad5586c2a109bbdbab1ad65a1a6f)