Commit 96e01e10 authored by Denis Filatov's avatar Denis Filatov
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Math support

parent 11772352
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+2 −2
Original line number Original line Diff line number Diff line
@@ -179,7 +179,7 @@ This is a complete set of observations for CAM. Application-specific
 backward (1) and the speedValue is greater than 3,000. (Usually, backward 
 backward (1) and the speedValue is greater than 3,000. (Usually, backward 
 drives are far less than 50m long, and with maximum possible acceleration of 
 drives are far less than 50m long, and with maximum possible acceleration of 
 9 m/s<sup>2</sup> (see trigger conditions for LongAcc-ValueTooLarge), max attainable 
 9 m/s<sup>2</sup> (see trigger conditions for LongAcc-ValueTooLarge), max attainable 
 speed is $\sqrt{2*9*50}$ m/s, i.e., 3,000 cm/s.)
 speed is $`\sqrt{2*9*50}`$ m/s, i.e., 3,000 cm/s.)


   - `Speed-ChangeTooLarge`: The acceleration calculated from the change 
   - `Speed-ChangeTooLarge`: The acceleration calculated from the change 
 in speedValue of two consecutive CAMs meets the trigger conditions of 
 in speedValue of two consecutive CAMs meets the trigger conditions of 
@@ -187,7 +187,7 @@ This is a complete set of observations for CAM. Application-specific


 - _SetMbObsEtsiOnlyLongAcc_:
 - _SetMbObsEtsiOnlyLongAcc_:
   - `LongAcc-ValueTooLarge`: The longitudinalAcceleration is greater 
   - `LongAcc-ValueTooLarge`: The longitudinalAcceleration is greater 
 than 90 dm/s<sup>2</sup>. (Typical $\mu$ (coefficient of friction between asphalt and 
 than 90 dm/s<sup>2</sup>. (Typical $`\mu`$ (coefficient of friction between asphalt and 
 rubber) is 0.9, so maximum possible acceleration is 0.9*9.8 m/s<sup>2</sup>, i.e., 
 rubber) is 0.9, so maximum possible acceleration is 0.9*9.8 m/s<sup>2</sup>, i.e., 
 88.2 dm/s<sup>2</sup>.)
 88.2 dm/s<sup>2</sup>.)
```asn1
```asn1